A plaque remaining from the Big Apple Night Club at West 135th Street and Seventh Avenue in Harlem.

Above, a 1934 plaque from the Big Apple Night Club at West 135th Street and Seventh Avenue in Harlem. Discarded as trash in 2006. Now a Popeyes fast food restaurant on Google Maps.

Recent entries:
“Unless you’re music, I don’t want to listen to you in the morning” (5/8)
“Took my own lunch to work and didn’t buy a coffee today so I should be able to afford to buy a house any day now” (5/8)
“Unless you’re music, I don’t wanna listen to you in the morning” (5/8)
Entry in progress—BP24 (5/8)
Entry in progress—BP23 (5/8)
More new entries...

A  B  C  D  E  F  G  H  I  J  K  L  M  N  O  P  Q  R  S  T  U  V  W  X  Y  Z


Entry from January 08, 2023
“Drink cheap wine, you’re an alcoholic; drink expensive wine, you’re a connoisseur”

“Drink enough cheap wine and you’re an alcoholic, but drink the same amount of expensive wine and you’re a connoisseur” was posted on Reddit—Showerthoughts on January 8, 2023.
 
     
Reddit—Showerthoughts
Posted by u/pufballcat January 8, 2023
Drink enough cheap wine and you’re an alcoholic, but drink the same amount of expensive wine and you’re a connoisseur
COMMENTS
Kmhutch327
“I’m not having one glass of wine. I’m having six. It’s called a tasting and it’s classy.”
   
Twitter
Zoor Kriid (💙,🧡)
@zoorkriid
Drink enough cheap wine and you’re an alcoholic, but drink the same amount of expensive wine and you’re a connoisseur /u/pufballcat
6:47 PM · Jan 8, 2023
 
Twitter
Peachez 💋
@PEACHMINAJ
Drink enough cheap wine and you’re an alcoholic, but drink the same amount of expensive wine and you’re a connoisseur
8:26 PM · Jan 8, 2023
 
Twitter
A Quote A Day  Jay Lim 𝄞 ❄️
@aQuoteAday
Drink enough cheap wine and you’re an alcoholic, but drink the same amount of expensive wine and you’re a connoisseur.
값싼 와인을 많이 마시면 알코올 중독자가 되지만 같은 양의 값비싼 와인을 마시면 와인감정가가 된다.
2:36 AM · Jan 9, 2023

Posted by Barry Popik
New York CityFood/Drink • Sunday, January 08, 2023 • Permalink


Commenting is not available in this channel entry.